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The problem states that the diploid chromosome number ($2n$) of the angiosperm is 36. Therefore, the haploid number ($n$) is calculated as: $$n = \frac{36}{2} = 18$$
In angiosperms, the endosperm is formed through the process of double fertilization, specifically the fusion of one male gamete ($n$) with two polar nuclei ($n + n$). This results in a triploid ($3n$) structure.
Using the haploid number ($n = 18$) determined in Step 1, the chromosome number in the triploid endosperm is: $$3n = 3 \times 18 = 54$$
Final Answer: 54