A comprehensive platform for Teachers to create standard question papers and Students to practice Case-Based, Assertion-Reason, and Critical Thinking questions.
Create professional PDF/Word papers with logo, instructions, and mixed question types in minutes.
Explore our repository by Class and Topic. Filter by "Knowledge" or "Competency" levels.
For Students. Take timed MCQ tests to check your understanding. Get instant feedback.
According to NEP 2020, rote learning is out. The focus has shifted to assessing a student's ability to apply concepts in real-life situations.
Questions derived from real-world passages to test analytical skills.
Testing the logic behind concepts, not just the definition.
Open-ended scenarios that require thinking beyond the textbook.
We provide complete AI-Powered Explanations for every question.
The magnitude of the cross product of two vectors $\vec{a}$ and $\vec{b}$ is given by: $$|\vec{a}\times\vec{b}| = |\vec{a}||\vec{b}|\sin\theta$$ where $\theta$ is the angle between the vectors $\vec{a}$ and $\vec{b}$, and $0 \le \theta \le \pi$.
Since $0 \le \theta \le \pi$, we know that $0 \le \sin\theta \le 1$. Therefore, $$|\vec{a}||\vec{b}|\sin\theta \le |\vec{a}||\vec{b}|$$ This implies that $$|\vec{a}\times\vec{b}| \le |\vec{a}||\vec{b}|$$
The equality $|\vec{a}\times\vec{b}| = |\vec{a}||\vec{b}|$ holds if and only if $\sin\theta = 1$. This occurs when $\theta = \frac{\pi}{2}$. Therefore, the vectors $\vec{a}$ and $\vec{b}$ must be perpendicular (orthogonal) to each other.
Final Answer: $|\vec{a}\times\vec{b}|\le|\vec{a}||\vec{b}|$. Equality holds when $\vec{a}$ and $\vec{b}$ are perpendicular.