Available Questions 58 found Page 1 of 3
Standalone Questions
#1486
Mathematics
Three Dimensional Geometry
LA
REMEMBER
2025
AISSCE(Board Exam)
Competency
5 Marks
Find the image of the point (-1,5,2) in the line $\frac{2x-4}{2}=\frac{y}{2}=\frac{2-z}{3}$. Find the length of the line segment joining the points (given point and the image point).
Key:
Sol:
Sol:
#1485
Mathematics
Three Dimensional Geometry
LA
REMEMBER
2025
AISSCE(Board Exam)
KNOWLEDGE
5 Marks
Find the point Q on the line $\frac{2x+4}{6}=\frac{y+1}{2}=\frac{-2z+6}{-4}$ at a distance of $3\sqrt{2}$ from the point $P(1,2,3)$.
Key:
Sol:
Sol:
#1480
Mathematics
Three Dimensional Geometry
SA
REMEMBER
2025
AISSCE(Board Exam)
KNOWLEDGE
3 Marks
Find the shortest distance between the lines: $\vec{r}=(2\hat{i}-\hat{j}+3\hat{k})+\lambda(\hat{i}-2\hat{j}+3\hat{k})$ and $\vec{r}=(\hat{i}+4\hat{k})+\mu(3\hat{i}-6\hat{j}+9\hat{k})$.
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Sol:
Sol:
#1464
Mathematics
Three Dimensional Geometry
LA
REMEMBER
2025
AISSCE(Board Exam)
Competency
5 Marks
Let the polished side of the mirror be along the line $\frac{x}{1}=\frac{1-y}{-2}=\frac{2z-4}{6}$. A point $P(1,6,3)$, some distance away from the mirror, has its image formed behind the mirror. Find the coordinates of the image point and the distance between the point P and its image.
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Sol:
Sol:
#1457
Mathematics
Three Dimensional Geometry
SA
REMEMBER
2025
AISSCE(Board Exam)
KNOWLEDGE
3 Marks
Let the position vectors of the points A, B and C be $3\hat{i}-\hat{j}-2\hat{k}$, $\hat{i}+2\hat{j}-\hat{k}$ and $\hat{i}+5\hat{j}+3\hat{k}$ respectively. Find the vector and cartesian equations of the line passing through A and parallel to line BC.
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Sol:
Sol:
#1456
Mathematics
Three Dimensional Geometry
SA
REMEMBER
2025
AISSCE(Board Exam)
KNOWLEDGE
3 Marks
Find the distance of the point $P(2,4,-1)$ from the line $\frac{x+5}{1}=\frac{y+3}{4}=\frac{z-6}{-9}$.
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Sol:
Sol:
#1449
Mathematics
Three Dimensional Geometry
VSA
REMEMBER
2025
AISSCE(Board Exam)
KNOWLEDGE
2 Marks
Determine if the lines $\vec{r}=(\hat{i}+\hat{j}-\hat{k})+\lambda(3\hat{i}-\hat{j})$ and $\vec{r}=(4\hat{i}-\hat{k})+\mu(2\hat{i}+3\hat{k})$ intersect with each other.
Key:
Sol:
Sol:
#1442
Mathematics
Three Dimensional Geometry
LA
REMEMBER
2025
AISSCE(Board Exam)
KNOWLEDGE
5 Marks
Find the point on the line $\frac{x-1}{3}=\frac{y+1}{2}=\frac{z-4}{3}$ at a distance of $2\sqrt{2}$ units from the point (-1, -1, 2).
Key:
Sol:
Sol:
#1441
Mathematics
Three Dimensional Geometry
LA
REMEMBER
2025
AISSCE(Board Exam)
KNOWLEDGE
5 Marks
Find the foot of the perpendicular drawn from the point (1, 1, 4) on the line $\frac{x+2}{5}=\frac{y+1}{2}=\frac{-z+4}{-3}$.
Key:
Sol:
Sol:
#1427
Mathematics
Three Dimensional Geometry
VSA
REMEMBER
2025
AISSCE(Board Exam)
KNOWLEDGE
2 Marks
A man needs to hang two lanterns on a straight wire whose end points have coordinates $A(4,1,-2)$ and $B(6,2,-3)$. Find the coordinates of the points where he hangs the lanterns such that these points trisect the wire AB.
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Sol:
Sol:
#1420
Mathematics
Three Dimensional Geometry
LA
REMEMBER
2025
AISSCE(Board Exam)
KNOWLEDGE
5 Marks
Find the equation of a line in vector and cartesian form which passes through the point $(1,2,-4)$ and is perpendicular to the lines $\frac{x-8}{3}=\frac{y+19}{-16}=\frac{z-10}{7}$ and $\vec{r}=15\hat{i}+29\hat{j}+5\hat{k}+\mu(3\hat{i}+8\hat{j}-5\hat{k})$.
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Sol:
Sol:
#1413
Mathematics
Three Dimensional Geometry
SA
UNDERSTAND
2025
AISSCE(Board Exam)
Competency
3 Marks
Find the distance of the point $(-1, -5, -10)$ from the point of intersection of the lines $\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}$ and $\frac{x-4}{5}=\frac{y-1}{2}=z$.
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Sol:
Sol:
#1396
Mathematics
Three Dimensional Geometry
LA
REMEMBER
2025
AISSCE(Board Exam)
Competency
5 Marks
Find the image A' of the point A(2, 1, 2) in the line $l:\vec{r}=4\hat{i}+2\hat{j}+2\hat{k}+\lambda(\hat{i}-\hat{j}-\hat{k})$. Also, find the equation of line joining AA'. Find the foot of perpendicular from point A on the line l.
Key:
Sol:
Sol:
#1395
Mathematics
Three Dimensional Geometry
LA
REMEMBER
2025
AISSCE(Board Exam)
KNOWLEDGE
5 Marks
Find the shortest distance between the lines: $\frac{x+1}{2}=\frac{y-1}{1}=\frac{z-9}{-3}$ and $\frac{x-3}{2}=\frac{y+15}{-7}=\frac{z-9}{5}$.
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Sol:
Sol:
#1375
Mathematics
Three Dimensional Geometry
LA
UNDERSTAND
2025
AISSCE(Board Exam)
Competency
5 Marks
Find a point P on the line $\frac{x+5}{1}=\frac{y+3}{4}=\frac{z-6}{-9}$ such that its distance from point $Q(2,4,-1)$ is 7 units. Also, find the equation of line joining P and Q.
Key:
Sol:
Sol:
#1374
Mathematics
Three Dimensional Geometry
LA
UNDERSTAND
2025
AISSCE(Board Exam)
Competency
5 Marks
Find the image A' of the point $A(1,6,3)$ in the line $\frac{x}{1}=\frac{y-1}{2}=\frac{z-2}{3}$. Also, find the equation of the line joining A and A'.
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Sol:
Sol:
#1366
Mathematics
Three Dimensional Geometry
SA
UNDERSTAND
2025
AISSCE(Board Exam)
Competency
3 Marks
Verify that lines given by $\vec{r}=(1-\lambda)\hat{i}+(\lambda-2)\hat{j}+(3-2\lambda)\hat{k}$ and $\vec{r}=(\mu+1)\hat{i}+(2\mu-1)\hat{j}-(2\mu+1)\hat{k}$ are skew lines. Hence, find shortest distance between the lines.
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Sol:
Sol:
#1353
Mathematics
Three Dimensional Geometry
LA
REMEMBER
2024
AISSCE(Board Exam)
Competency
5 Marks
Find the shortest distance between the lines $L_{1}$ & $L_{2}$ given below :
$L_{1}$: The line passing through (2, -1, 1) and parallel to $\frac{x}{1}=\frac{y}{1}=\frac{z}{3}$ and
$L_{2}:\vec{r}=\hat{i}+(2\mu+1)\hat{j}-(\mu+2)\hat{k}$
$L_{1}$: The line passing through (2, -1, 1) and parallel to $\frac{x}{1}=\frac{y}{1}=\frac{z}{3}$ and
$L_{2}:\vec{r}=\hat{i}+(2\mu+1)\hat{j}-(\mu+2)\hat{k}$
Key:
Sol:
Sol:
#1352
Mathematics
Three Dimensional Geometry
LA
UNDERSTAND
2024
AISSCE(Board Exam)
Competency
5 Marks
Find the co-ordinates of the foot of the perpendicular drawn from the point (2, 3, -8) to the line $\frac{4-x}{2}=\frac{y}{6}=\frac{1-z}{3}$ Also, find the perpendicular distance of the given point from the line.
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Sol:
Sol:
#1339
Mathematics
Three Dimensional Geometry
VSA
APPLY
2024
AISSCE(Board Exam)
KNOWLEDGE
2 Marks
Find the vector equation of the line passing through the point (2, 3, -5) and making equal angles with the co-ordinate axes.
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Sol:
Sol: