A comprehensive platform for Teachers to create standard question papers and Students to practice Case-Based, Assertion-Reason, and Critical Thinking questions.
Create professional PDF/Word papers with logo, instructions, and mixed question types in minutes.
Explore our repository by Class and Topic. Filter by "Knowledge" or "Competency" levels.
For Students. Take timed MCQ tests to check your understanding. Get instant feedback.
According to NEP 2020, rote learning is out. The focus has shifted to assessing a student's ability to apply concepts in real-life situations.
Questions derived from real-world passages to test analytical skills.
Testing the logic behind concepts, not just the definition.
Open-ended scenarios that require thinking beyond the textbook.
We provide complete AI-Powered Explanations for every question.
Let the general points on the two lines be $P(2\lambda+1, 3\lambda+2, 4\lambda+3)$ and $Q(5\mu+4, 2\mu+1, \mu)$. For intersection, $P=Q$: $$2\lambda+1 = 5\mu+4 \implies 2\lambda - 5\mu = 3$$ $$3\lambda+2 = 2\mu+1 \implies 3\lambda - 2\mu = -1$$ Solving these, multiply first by 3 and second by 2: $6\lambda - 15\mu = 9$ and $6\lambda - 4\mu = -2$. Subtracting gives $-11\mu = 11 \implies \mu = -1$. Substituting $\mu = -1$ into $3\lambda - 2(-1) = -1 \implies 3\lambda = -3 \implies \lambda = -1$. The point is $(-1, -1, -1)$.
The line passes through $\vec{a} = -\hat{i} - \hat{j} - \hat{k}$ and is parallel to $\vec{b} = 3\hat{i} + 2\hat{j} - 8\hat{k}$. The vector equation is $\vec{r} = \vec{a} + \lambda\vec{b}$: $$\vec{r} = (-\hat{i} - \hat{j} - \hat{k}) + \lambda(3\hat{i} + 2\hat{j} - 8\hat{k})$$
Using the point $(x_1, y_1, z_1) = (-1, -1, -1)$ and direction ratios $(a, b, c) = (3, 2, -8)$, the equation is: $$\frac{x+1}{3} = \frac{y+1}{2} = \frac{z+1}{-8}$$
Final Answer: Vector: \vec{r} = (-\hat{i} - \hat{j} - \hat{k}) + \lambda(3\hat{i} + 2\hat{j} - 8\hat{k}); Cartesian: \frac{x+1}{3} = \frac{y+1}{2} = \frac{z+1}{-8}