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Standalone Questions
#707
Mathematics
Practice
MCQ_SINGLE
APPLY
MEDIUM
2023
KNOWLEDGE
4 Marks
A particle moves along a straight line such that its displacement x changes with time t as x = t^3 - 6t^2 + 3t + 4. What is the velocity when acceleration is zero?
Key: -9 m/s
Sol:
Sol:
Velocity v = dx/dt = 3t^2 - 12t + 3. Acceleration a = dv/dt = 6t - 12. For a=0, 6t=12 => t=2s. At t=2, v = 3(4) - 12(2) + 3 = -9.
#705
Mathematics
Statistics and Probability