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The highest occupied molecular orbital for $Ne_{2}$ is

Consider the following reaction sequences and choose the correct option.

Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R. Assertion A: The first ionization enthalpy of O is lower than that of N and F. Reason R: The loss of an electron from O leads to stable half-filled p orbital. In light of the above statements, choose the most appropriate answer from the options given below:

Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R. Assertion A: Generally, 3d transition metals have high melting points. Reason R: Involvement of 3d-electrons in addition to 3s-electrons in the interatomic metallic bonding. In light of the above statements, choose the most appropriate answer from the options given below:

A protein undergoes reversible thermal denaturation from its initial state N to denatured state D according to $N \rightleftharpoons D$. At $60^{\circ}C$, the concentrations of both N and D are equal at equilibrium, and the standard enthalpy change of denaturation is $666~kJ~mol^{-1}$. The standard entropy change ($\Delta S^{\circ}$ in $kJ~K^{-1}~mol^{-1}$) of the protein upon denaturation at $60^{\circ}C$ is closest to

Among the species given below, the spin-only magnetic moment is highest for (Given: Atomic number of $Ti=22$, $Mn=25$, $Fe=26$ and $Co=27$)

Assertion A: For an ideal solution formed by mixing liquids P and Q, $\Delta_{mix}H=0$ and $\Delta_{mix}V=0$. Reason R: No interactions occur between P and Q. In the light of the above statements, choose the most appropriate answer from the options given below.

The correct decreasing order of oxidation state of the underlined atom in each molecule is

The correct order of solubility of the given salts in water at 298 K is: Salt | $K_{sp}$ at 298 K: AgBr | $5.0\times10^{-13}$, $Zn(OH)_{2}$ | $1.0\times10^{-15}$, $Hg_{2}Cl_{2}$ | $1.3\times10^{-18}$

$2A\rightarrow B$ is a zero-order reaction, where $k=1.0~mol~L^{-1}min^{-1}$. If the initial concentration of A is 2 M, then the time taken to complete 75% of the reaction will be

Among the following, the compound having conjugated double bonds is

In an acidic medium, 10 mL of 0.25 M oxalic acid is titrated with $KMnO_{4}$ solution. If the volume of $KMnO_{4}$ solution required to reach end point is 10 mL, the strength of the $KMnO_{4}$ solution is

The amino acid that gives a red-blood colour on treating its sodium fusion extract with sodium nitroprusside is

Arrange the following compounds in the increasing order of polarity: A. $CH_{3}CH_{2}OCH_{2}CH_{3}$, B. $CH_{3}CH_{2}OH$, C. $CH_{3}COCH_{3}$, D. $CH_{3}COOH$. Choose the correct answer from the options given below.

For a salt XY, which is a strong electrolyte, the plot of $\Lambda_{m}$ versus $\sqrt{c}$ has a slope of $-90.0~S~cm^{2}mol^{-3/2}L^{1/2}$ at 298 K. At 0.01 M concentration of XY, the value of $\Lambda_{m}$ is $145.0~S~cm^{2}mol^{-1}$. The limiting molar conductivity of $Y^{-}$ ion $(\lambda_{Y^{-}}^{0}$, in $S~cm^{2}~mol^{-1}$) at 298 K will be (Given : $\lambda_{X^{+}}^{0}=74.0~S~cm^{2}mol^{-1})$

Consider the following statements about the solutions formed by mixing two liquids. A. An ideal solution thus formed obeys Raoult's law throughout the composition range. B. Mixture of chloroform and acetone shows negative deviation from Raoult's law. C. Mixture of aniline and phenol shows positive deviation from Raoult's law. Choose the correct option:

The standard electrode potential $(E^{\circ})$ for the half-cell reaction $Fe^{3+}+e^{-}\rightarrow Fe^{2+}$ at 298 K is (Given: $E^{\circ}(Fe^{3+}/Fe)=-0.041$ V and $E^{\circ}(Fe^{2+}/Fe)=-0.44$ V at 298 K)

The amount of carbon dioxide evolved upon complete combustion of 116 g of n-butane is (Given: atomic mass in amu $H=1$, $C=12$ and $O=16$)

The numbers 17.0145 and 21.0235 were rounded to three figures after the decimal point. The resulting numbers, respectively, are

The complex which has facial and meridional isomers is (Given: py = pyridine and en = $H_{2}N-CH_{2}-CH_{2}-NH_{2}$)