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A matrix is singular if its determinant is zero.
Calculate the determinant of the given matrix:
det(\(\begin{bmatrix}4+x&x-1\\ -2&3\end{bmatrix}\)) = (4+x)(3) - (x-1)(-2)
Set the determinant equal to zero:
(4+x)(3) - (x-1)(-2) = 0
Expand and simplify the equation:
12 + 3x + 2x - 2 = 0
5x + 10 = 0
Solve for x:
5x = -10
x = -2
Correct Answer: -2
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